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An edition of Complex variables and applications Verify properties 3 and 4 of conjugates in Sec. Use property 4 of conjugates in Sec.
Verify property 9 of moduli in Sec. Use results in Sec. It is shown in Sec. Give an alternative proof based on the corresponding result for real numbers and using identity 8 , Sec.
Using expressions 6 , Sec. Follow the steps below to give an algebraic derivation of the triangle inequality Sec. Its use in Sec. This can be seen vectorially Fig. It is easily verified for positive values of n by mathematical induction. Expression 4 is thus verified when n is a positive integer. Expression 4 is now established for all integral powers.
The following example uses a special case of it. See also Exercises 10 and 11, Sec. See Fig. But, as the following example illustrates, that is not always the case. Statement 4 is, then, to be interpreted in the same way that statement 2 is. It is, therefore, evident from Fig.
Finally, a convenient way to remember expression 1 is to write z 0 in its most general exponential form compare with Example 2 in Sec. The examples in the next section serve to illustrate this method for finding roots of complex numbers.
Note how it follows from expressions 2 and 4 in Sec. In view of expression 3 , Sec. Let a denote any positive real number. According to Sec. Suggestion: Use the first identity in Exercise 9, Sec. Compare with Exercise 7, Sec. If z 0 is neither of these, it is a boundary point of S. A boundary point is, therefore, a point all of whose neighborhoods contain at least one point in S and at least one point not in S. The totality of all boundary points is called the boundary of S. It is left as an exercise to show that a set is open if and only if each of its points is an interior point.
A set is closed if it contains all of its boundary points, and the closure of a set S is the closed set consisting of all points in S together with the boundary of S. Note that the first of sets 3 is open and that the second is its closure.
Some sets are, of course, neither open nor closed. For a set S to be not open there must be a boundary point that is contained in the set, and for S to be not closed there SEC.
It follows that if a set S is closed, then it contains each of its accumulation points. For if an accumulation point z 0 were not in S, it would be a boundary point of S; but this contradicts the fact that a closed set contains all of its boundary points.
It is left as an exercise to show that the converse is, in fact, true. Thus a set is closed if and only if it contains all of its accumulation points. Evidently, a point z 0 is not an accumulation point of a set S whenever there exists some deleted neighborhood of z 0 that does not contain at least one point in S. Which sets in Exercise 1 are neither open nor closed? Which sets in Exercise 1 are bounded?
The main goal of the chapter is to introduce analytic functions, which play a central role in complex analysis. A function f defined on S is a rule that assigns to each z in S a complex number w. The set S is called the domain of definition of f.
When the domain of definition is not mentioned, we agree that the largest possible set is to be taken. Also, it is not always convenient to use notation that distinguishes between a given function and its values. If the function v in equation 1 always has value zero, then the value of f is always real. Thus f is a real-valued function of a complex variable. Note that the sum here has a finite number of terms and that the domain of definition is the entire z plane.
Polynomials and rational functions constitute elementary, but important, classes of functions of a complex variable. A generalization of the concept of function is a rule that assigns more than one value to a point z in the domain of definition. These multiple-valued functions occur SEC. When multiple-valued functions are studied, usually just one of the possible values assigned at each point is taken, in a systematic manner, and a single-valued function is constructed from the multiple-valued one.
Let z denote any nonzero complex number. We know from Sec. More information is usually exhibited by sketching images of curves and regions than by simply indicating images of individual points. This form of the mapping is especially useful in finding the images of certain hyperbolas.
Suppose that x, y is on the branch lying in the first quadrant. As a point on the first circle moves counterclockwise from the positive real axis to the positive imaginary axis, its image on the second circle moves counterclockwise from the positive real axis to the negative real axis see Fig.
So, as all possible positive values of r0 are chosen, the corresponding arcs in the z and w planes fill out the first quadrant and the upper half plane, respectively. This mapping of the first quadrant onto the upper half plane can also be verified using the rays indicated by dashes in Fig.
Details of the verification are left to Exercise 7. However, in this case, the transformation is not one to one since both the positive and negative real axes in the z plane are mapped onto the positive real axis in the w plane. Such a transformation maps the entire z plane onto the entire w plane, where each nonzero point in the w plane is the image of n distinct points in the z plane. Use the expressions see Sec. By referring to the discussion in Sec.
Use rays indicated by dashed half lines in Fig. The function assigns a vector w, with components u x, y and v x, y , to each point z at which it is defined.
Indicate graphically the vector fields represented by z. We now express the definition of limit in a precise and usable form. When a limit of a function f z exists at a point z 0 , it is unique. Definition 2 requires that f be defined at all points in some deleted neighborhood of z 0. Such a deleted neighborhood, of course, always exists when z 0 is an interior point of a region on which f is defined.
We can extend the definition of limit to the case in which z 0 is a boundary point of the region by agreeing that the first of inequalities 2 need be satisfied by only those points z that lie in both the region and the deleted neighborhood. The next example emphasizes this. Since a limit is unique, we must conclude that limit 5 does not exist.
While definition 2 provides a means of testing whether a given point w0 is a limit, it does not directly provide a method for determining that limit. Theorems on limits, presented in the next section, will enable us to actually find many limits. Since limits of the latter type are studied in calculus, we may use their definition and properties freely.
Theorem 1. To prove the theorem, we first assume that limits 1 hold and obtain limit 2. If two functions are continuous at a point, their sum and product are also continuous at that point; their quotient is continuous at any such point if the denominator is not zero there.
These observations are direct consequences of Theorem 2, Sec. Note, too, that a polynomial is continuous in the entire plane because of limit 11 in Sec. We turn now to two expected properties of continuous functions whose verifications are not so immediate. Our proofs depend on definition 4 of continuity, and we present the results as theorems. A composition of continuous functions is itself continuous. A precise statement of this theorem is contained in the proof to follow. Solve equations 2 , Sec.
Thus complete the verification that equations 6 , Sec. Use the expressions for u x and vx found in Exercise 5, together with the polar form 6 , Sec. A function f of the complex variable z is analytic in an open set S if it has a derivative everywhere in that set.
It is analytic at a point z 0 if it is analytic in some neighborhood of z 0. If we should speak of a function that is analytic in a set S that is not open, it is to be understood that f is analytic in an open set containing S. An entire function is a function that is analytic at each point in the entire plane. See Example 3, Sec. Finally, since the derivative of a polynomial exists everywhere, it follows that every polynomial is an entire function.
A necessary, but by no means sufficient, condition for a function to be analytic in a domain D is clearly the continuity of f throughout D. See the statement in italics near the end of Sec. Satisfaction of the Cauchy—Riemann equations is also necessary, but not sufficient. Sufficient conditions for analyticity in D are provided by the theorems in Secs.
Other useful sufficient conditions are obtained from the rules for differentiation in Sec. The derivatives of the sum and product of two functions exist wherever the functions themselves have derivatives. Thus, if two functions are analytic in a domain D, their sum and their product are both analytic in D.
Similarly, their quotient is analytic in D provided the function in the denominator does not vanish at any point in D. More precisely, suppose that a function f z is analytic in a domain D and that the image Sec. Next, we show that u x, y is constant along any line segment L extending from a point P to a point P and lying entirely in D.
We let s denote the distance along L from the point P and let U denote the unit vector along L in the direction of increasing s see Fig. If a function f fails to be analytic at a point z 0 but is analytic at some point in every neighborhood of z 0 , then z 0 is called a singular point, or singularity, of f.
Singular points will play an important role in our development of complex analysis in chapters to follow. The analyticity is due to the existence of familiar differentiation rules, which need to be applied only if an expression for f z is actually wanted.
When a function is given in terms of its component functions u and v, its analyticity can be determined by direct application of the Cauchy—Riemann equations.
The next two examples serve to illustrate how the Cauchy—Riemann equations can be used to obtain various properties of analytic functions. Let us show that f z must, then, be constant throughout D. According to expression 8 in Sec. As in Example 3, we consider a function f that is analytic throughout a given domain D. Assuming further that the modulus f z is constant throughout D, one can prove that f z must be constant there too. This result is needed to obtain an important result later on in Chap.
The main result in Example 3 just above thus ensures that f z is constant throughout D. Apply the theorem in Sec. With the aid of the theorem in Sec. State why a composition of two entire functions is entire. According to Example 2, Sec. Let a function f be analytic everywhere in a domain D. Prove that if f z is real-valued for all z in D, then f z must be constant throughout D.
Harmonic functions play an important role in applied mathematics. For example, the temperatures T x, y in thin plates lying in the x y plane are often harmonic. A function V x, y is harmonic when it denotes an electrostatic potential that varies only with x and y in the interior of a region of three-dimensional space that is free of charges. It also assumes the values on the edges of the strip that are indicated in Fig.
To show this, we need a result that is to be proved in Chap. Namely, if a function of a complex variable is analytic at a point, then its real and imaginary components have continuous partial derivatives of all orders at that point. That is, u and v are harmonic in D. Taylor and W. Further discussion of harmonic functions related to the theory of functions of a complex variable appears in Chaps.
Using the Cauchy—Riemann equations in polar coordinates Sec. Prove that these families are orthogonal. Note the orthogonality of the two families, described in Exercise 2. Why is this fact in agreement with the result in Exercise 2? Do Exercise 4 using polar coordinates. While these sections are of considerable theoretical interest, they are not central to our development of analytic functions in later chapters.
The reader may pass directly to Chap. Since D is a connected open set Sec. We let d be the shortest distance from points on L to the boundary of D, unless D is the entire plane; in that case, d may be any positive number.
We then form a finite SEC. Finally, we construct a finite sequence of neighborhoods N0 , N1 , N2 ,. Namely, Theorem 3 in Sec. But the point z 1 lies in N0. This completes the proof of the lemma. We thus arrive at the following important theorem. A function that is analytic in a domain D is uniquely determined over D by its values in a domain, or along a line segment, contained in D. A more general result, sometimes called the coincidence principle, is straightforward to prove.
I of the book by Markushevich, all of which are listed in Appendix 1. If D1 and D2 have points in common see Fig. If so, we call f 2 an analytic continuation of f 1 into the second domain D2. However, if there is an analytic continuation f 3 of f 2 from D2 into a domain D3 which intersects D1 , as indicated in Fig.
Exercise 2, Sec. Suppose that a function f is analytic in some domain D which contains a segment of the x axis and whose lower half is the reflection of the upper half with respect to that axis. We start the proof by assuming that f x is real at each point x on the segment. Inasmuch as the first-order partial derivatives of U x, y and V x, y are now shown to satisfy the Cauchy— Riemann equations and since those derivatives are continuous, we find that the function F z is analytic in D.
According to the theorem in Sec. Hence f x is real on the segment of the real axis lying in D. Use the theorem in Sec. Suggestion: Suppose that f z does have a constant value w0 throughout some neighborhood in D. We know from Example 1, Sec. Point out how it follows from the reflection principle Sec.
Then verify this directly. Show that if the condition that f x is real in the reflection principle Sec. We start by defining the complex exponential function and then use it to develop the others. This is an exception to the convention Sec. In addition to property 4 , there are a number of other properties that carry over from e x to e z , and we mention a few of them here.
But x1 and x2 are both real, and we know from Sec. Property 5 is now established. There are a number of other important properties of e z that are expected.
According to Example 1 in Sec. Note that the differentiability of e z for all z tells us that e z is entire Sec. We recall Sec. There are, moreover, values of z such that e z is any given nonzero complex number. This is shown in the next section, where the logarithmic function is developed, and is illustrated in the following example.
Then, in view of the statement in italics at the beginning of Sec. Use the Cauchy—Riemann equations and the theorem in Sec. What is its derivative? Compare with Exercise 4, Sec. Why is this function harmonic in every domain that does not contain the origin? It should be emphasized that it is not true that the left-hand side of equation 3 with the order of the exponential and logarithmic functions reversed reduces to just z.
It reduces to the usual logarithm in calculus when z is a positive real number. From expression 2 in Sec. The next example reminds us that although we were unable to find logarithms of negative real numbers in calculus, it is now possible. Special care must be taken in anticipating that familiar properties of ln x in calculus carry over to be properties of log z and Log z.
It is shown in Exercise 5, Sec. Furthermore, according to Sec. A branch cut is a portion of a line or curve that is introduced in order to define a branch F of a multiple-valued function f.
Points on the branch cut for F are singular points Sec. The origin is evidently a branch point for branches of the multiple-valued logarithmic function. The following example does show, however, that equality can occur when a specific branch of the logarithm is used. In that case, of course, there is only one value of log i 2 that is to be taken, and the same is true of 2 log i.
In Sec. A reader who wishes to pass to Sec. Show that a branch Sec. Then, using the theorem in Sec. That is, if values of two of the three logarithms are specified, then there is a value of the third such that equation 1 holds.
The verification of statement 1 can be based on statement 2 in the following way. Finally, because of the way in which equations 1 and 2 are to be interpreted, equation 3 is the same as equation 1. Thus statement 1 is not always true when principal values are used in all three terms. In our next example, however, principal values can be used everywhere in equation 1 when certain restrictions are placed on the nonzero numbers z 1 and z 2.
Compare this result with the one in Exercise 6, Sec. We include here two other properties of log z that will be of special interest in Sec. Then, in view of definition 2 , Sec. That right-hand side is, in fact, an expression for the nth roots of z Sec.
This establishes property 6 , which is actually valid when n is a negative integer too see Exercise 4. Compare with Example 2 in Sec. Verify expression 4 , Sec. By choosing specific nonzero values of z 1 and z 2 , show that expression 4 , Sec. Show that property 6 , Sec. Because of the logarithm, z c is, in general, multiple-valued. This will be illustrated in the next section. Equation 1 provides a consistent definition of z c in the sense that it is already known to be valid see Sec.
Definition 1 is, in fact, suggested by those particular choices of c. We mention here two other expected properties of the power function z c.
When a specific branch Sec. When that branch is used, the function 1 is single-valued and analytic in the same domain. This is because the principal value of log e is unity. When a value of log c is specified, c z is an entire function of z. Use definition 1 , Sec. What additional restriction must be placed on the constant c so that the values of i c are all the same?
A variety of identities carry over from trigonometry. Observe that once expression 13 is obtained, relation 14 also follows from the fact Sec. Expressions 13 and 14 can be used Exercise 7, Sec. Inasmuch as sinh y tends to infinity as y tends to infinity, it is clear from these two equations that sin z and cos z are not bounded on the complex plane, whereas the absolute values of sin x and cos x are less than or equal to unity for all values of x.
See the definition of a bounded function at the end of Sec. It is possible that a function of a real variable can have more zeros when the domain of definition is enlarged. One might ask if there are other zeros in the entire plane, and a similar question can be asked regarding the cosine function. The zeros of sin z and cos z in the complex plane are the same as the zeros of sin x and cos x on the real line.
Hence the zeros of sin z are as stated in the theorem. As for the cosine function, the second of relations 8 in Sec. A reader who wishes at this time to learn some of those properties is sufficiently prepared to read Secs.
Give details in the derivation of expressions 2 , Sec. Then use relations 3 , Sec. Verify identity 9 in Sec. Use identity 9 in Sec. Establish differentiation formulas 3 and 4 in Sec. Point out how it follows from expressions 15 and 16 in Sec. With the aid of expressions 15 and 16 in Sec. Use the reflection principle Sec.
With the aid of expressions 13 and 14 in Sec. With the aid of expression 14 , Sec. While these identities follow directly from definitions 1 , they are often more easily obtained from related trigonometric identities, with the aid of relations 3 and 4. Let us verify expression 12 using the second of relations 4. We turn now to the zeros of sinh z and cosh z.
We present the results as a theorem in order to emphasize their importance in later chapters and in order to provide easy comparison with the theorem in Sec. In fact, the theorem here is an immediate consequence of relations 4 and that earlier theorem. The zeros of sinh z and cosh z in the complex plane all lie on the imaginary axis.
The functions coth z, sech z, and csch z are the reciprocals of tanh z, cosh z, and sinh z, respectively. Verify that the derivatives of sinh z and cosh z are as stated in equations 2 , Sec. Show how identities 6 and 8 in Sec. Derive expression 11 in Sec. Give details showing that the zeros of sinh z and cosh z are as in the theorem in Sec.
Using the results proved in Exercise 8, locate all zeros and singularities of the hyperbolic tangent function. Suggestion: Use identities 4 in Sec. Derive differentiation formulas 17 , Sec. By accepting that the stated identity is valid when z is replaced by the real variable x and using the lemma in Sec. Why is the function sinh e z entire? Write its real component as a function of x and y, and state why that function must be harmonic everywhere.
By using one of the identities 9 and 10 in Sec. Compare this exercise with Exercise 16, Sec. When specific branches of the square root and logarithmic functions are used, all three inverse functions become single-valued and analytic because they are then compositions of analytic functions. The derivatives of these three functions are readily obtained from their logarithmic expressions. Derive expression 5 , Sec. Derive expression 4 , Sec. Derive expression 7 , Sec. Derive expression 9 , Sec.
The theory of integration, to be developed in this chapter, is noted for its mathematical elegance. The theorems are generally concise and powerful, and many of the proofs are short.
Various rules learned in calculus, such as the ones for differentiating sums and products, apply just as they do for real-valued functions of a real variable t. Verifications can often be based on corresponding rules in calculus. While many rules in calculus carry over to functions of the type 1 , not all of them do. The following example illustrates this. Such a function is continuous everywhere in the stated interval except possibly for a finite number of points where, although discontinuous, it has one-sided limits.
Of course, only the right-hand limit is required at a; and only the left-hand limit is required at b. When both u and v are piecewise continuous, the function w is said to have that property. Anticipated rules for integrating a complex constant times a function w t , for integrating sums of such functions, and for interchanging limits of integration are all valid.
Since see Example 2 in Sec. Our final example here shows that the mean value theorem for integrals does not carry over either.
Thus special care must continue to be used in applying rules from calculus. In order to show that it is not necessarily true that there is a number c in the interval a SEC. According to definition 2 , Sec.
Suggestion: In each part of this exercise, use the corresponding property of integrals of real-valued functions of t, which is graphically evident. CONTOURS Integrals of complex-valued functions of a complex variable are defined on curves in the complex plane, rather than on just intervals of the real line. Classes of curves that are adequate for the study of such integrals are introduced in this section.
Such a curve is positively oriented when it is in the counterclockwise direction. The geometric nature of a particular arc often suggests different notation for the parameter t in equation 2. This is, in fact, the case in the following examples. The polygonal line Sec. The same set of points can make up different arcs. The set of points is the same, but now the circle is traversed in the clockwise direction. The arc here differs, however, from each of those arcs since the circle is traversed twice in the counterclockwise direction.
The parametric representation used for any given arc C is, of course, not unique. It is, in fact, possible to change the interval over which the parameter ranges to any CHAP.
Thus the same length of C would be obtained if representation 10 were to be used. Suggestion: These identities can be obtained by noting that they are valid for realvalued functions of t. The special case in which C is a simple closed polygon is proved on pp. Verify expression 14 , Sec. It is, therefore, a line integral; and its value depends, in general, on the contour C as well as on the function f. Definite integrals in calculus can be interpreted as areas, and they have other interpretations as well.
Except in special cases, no corresponding helpful interpretation, geometric or physical, is available for integrals in the complex plane. We assume that f [z t ] is piecewise continuous Sec. I of the book by Markushevich that is listed in Appendix 1. The value of a contour integral is invariant under a change in the representation of its contour when the change is of the type 11 , Sec.
This can be seen by following the same general procedure that was used in Sec. This follows from definition 2 and properties of integrals of complex-valued functions w t mentioned in Sec. C Finally, consider a path C, with representation 1 , that consists of a contour C1 from z 1 to z 2 followed by a contour C2 from z 2 to z 3 , the initial point of C2 being the final point of C1 Fig. C2 We defer development of antiderivatives until Sec.
We begin here by letting C denote an arbitrary smooth arc Sec. The question of predicting when contour integrals are independent of path or always have value zero when the path is closed will be taken up in Secs.
The next two examples illustrate this. This exercise demonstrates how the value of an integral of a power function depends in general on the branch that is used. With the aid of the result in Exercise 3, Sec. Let C denote the semicircular path shown in Fig. Suggestion: In part a , use the result in Exercise 1 b , Sec. We present the result as a theorem but preface it with a needed lemma involving functions w t of the type encountered in Secs.
Let C denote a contour of length L , and suppose that a function f z is piecewise continuous on C. C a Since the integral on the right here represents the length L of C see Sec. It is, of course, a strict inequality if inequality 5 is strict.
Note that since C is a contour and f is piecewise continuous on C, a number M such as the one appearing in inequality 5 will always exist. The same is, then, true when f is piecewise continuous on C. Apply inequality 1 , Sec. Recall statements a and b at the end of Sec. Those statements also remind us of the fact that the values of integrals around closed paths are sometimes, but not always, zero.
Our next theorem is useful in determining when integration is independent of path and, moreover, when an integral around a closed path has value zero. The theorem contains an extension of the fundamental theorem of calculus that simplifies the evaluation of many contour integrals. Note that an antiderivative is, of necessity, an analytic function. Note, too, that an antiderivative of a given function f z is unique except for an additive constant.
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